Java实现网络监听
发布时间:2019-12-12 08:08:13 所属栏目:MsSql教程 来源:蓝点
导读:// tcpServer.java by fpont 3/2000 . // default port is 1500. // connection to be closed by client. // this server handles only 1 connection. import java.io.*; ServerSocket server_socket; BufferedReader input; try { port = Integer.parseInt
// tcpServer.java by fpont 3/2000 . // default port is 1500. // connection to be closed by client. // this server handles only 1 connection. BufferedReader input; try { port = Integer.parseInt(args[0]); } catch (Exception e) { System.out.println("port = 1500 (default)"); port = 1500; } System.out.println("Server waiting for client on port " + server_socket.getLocalPort()); // server infinite loop while(true) { Socket socket = server_socket.accept(); System.out.println("New connection accepted " + socket.getInetAddress() + ":" + socket.getPort()); input = new BufferedReader(new InputStreamReader(socket.getInputStream())); // print received data try { while(true) { String message = input.readLine(); if (message==null) break; System.out.println(message); } } catch (IOException e) { System.out.println(e); } try { socket.close(); System.out.println("Connection closed by client"); } catch (IOException e) { System.out.println(e); } } } catch (IOException e) { System.out.println(e); } } } // default port is 1500 Socket socket = null; String lineToBeSent; BufferedReader input; PrintWriter output; int ERROR = 1; if(args.length == 2) { server = args[0]; try { port = Integer.parseInt(args[1]); } catch (Exception e) { System.out.println("server port = 1000 (default)"); port = 1500; } } try { socket = new Socket(server, port); System.out.println("Connected with server " + socket.getInetAddress() + ":" + socket.getPort()); } catch (UnknownHostException e) { System.out.println(e); System.exit(ERROR); } catch (IOException e) { System.out.println(e); System.exit(ERROR); } input = new BufferedReader(new InputStreamReader(System.in)); output = new PrintWriter(socket.getOutputStream(),true); while(true) { lineToBeSent = input.readLine(); // stop if input line is "." if(lineToBeSent.equals(".")) break; output.println(lineToBeSent); } } catch (IOException e) { System.out.println(e); } } catch (IOException e) { System.out.println(e); } } } (编辑:西双版纳站长网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |